MIAMI GARDENS, Fla. — Miami Dolphins quarterback Tua Tagovailoa is the AFC's offensive player of the week.
The NFL announced Wednesday that Tagovailoa has been named the AFC's top offensive player after his six-touchdown performance in Miami's 42-38 comeback win at Baltimore.
Tagovailoa completed 36-of-50 passes for 469 yards and six touchdowns – all of which were career highs.
The Dolphins rallied from 21 down in the fourth quarter to defeat the Ravens. It was the largest fourth-quarter comeback and largest road comeback in team history.
Tagovailoa's six passing touchdowns tied a team record, while his 469 passing yards rank fourth in single-game team history.
This is the first such weekly award for the 2020 No. 5 overall pick. It's also the first time a Miami player has received the honor since now-retired quarterback Ryan Fitzpatrick in 2019.
